用c語言畫一個(gè)2次函數(shù)圖像

#include?windows.h

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LRESULT?CALLBACK?WndProc(HWND,?UINT,?WPARAM,?LPARAM);

int?WINAPI?WinMain(HINSTANCE?hInstance,?HINSTANCE?hPrevInstance,

PSTR?szCmdLine,?int?iCmdShow)

{

static?TCHAR?szAppName[]=TEXT("二次函數(shù)");

HWND?????????hwnd;

MSG??????????msg;

WNDCLASS?????wndclass;

wndclass.style=CS_HREDRAW|CS_VREDRAW;

wndclass.lpfnWndProc=WndProc;

wndclass.cbClsExtra=0;

wndclass.cbWndExtra=0;

wndclass.hInstance=hInstance;

wndclass.hIcon=LoadIcon(NULL,?IDI_APPLICATION);

wndclass.hCursor=LoadCursor(NULL,?IDC_ARROW);

wndclass.hbrBackground=(HBRUSH)GetStockObject(WHITE_BRUSH);

wndclass.lpszMenuName=NULL;

wndclass.lpszClassName=szAppName;

if?(!RegisterClass(wndclass))

{

MessageBox(NULL,?TEXT("Error"),

szAppName,?MB_ICONERROR);

return?0;

}

hwnd=CreateWindow(szAppName,?TEXT("二次函數(shù)"),

WS_OVERLAPPEDWINDOW,

CW_USEDEFAULT,?CW_USEDEFAULT,

CW_USEDEFAULT,?CW_USEDEFAULT,

NULL,?NULL,?hInstance,?NULL);

ShowWindow(hwnd,?iCmdShow);

UpdateWindow(hwnd);

while?(GetMessage(msg,?NULL,?0,?0))

{

TranslateMessage(msg);

DispatchMessage(msg);

}

return?msg.wParam;

}

LRESULT?CALLBACK?WndProc(HWND?hwnd,?UINT?message,?WPARAM?wParam,?LPARAM?lParam)

{

static?int??cxClient,?cyClient;

const?static?int?n=1000;

HDC?????????hdc;

int?????????i;

PAINTSTRUCT?ps;

POINT???????apt[n];

switch?(message)

{

case?WM_SIZE:

cxClient=LOWORD(lParam);

cyClient=HIWORD(lParam);

return?0;

case?WM_PAINT:

hdc=BeginPaint(hwnd,?ps);

MoveToEx(hdc,?0,?cyClient/2,?NULL);

LineTo(hdc,?cxClient,?cyClient/2);

MoveToEx(hdc,?cxClient/2,?0,?NULL);

LineTo(hdc,?cxClient/2,?cyClient);

for?(i=0;?i??n;++i)

{

apt[i].x=cxClient/4+i; apt[i].y=cyClient-(cyClient/2-i)*(cyClient/2-i)/300-cyClient/2+100;

}

Polyline(hdc,?apt,?n);

return?0;

case?WM_DESTROY:

PostQuitMessage(0);

return?0;

}

return?DefWindowProc(hwnd,?message,?wParam,?lParam);

}

幫我看看求二次函數(shù)的C語言程序，要求要用函數(shù)來寫，謝了

我已經(jīng)按你的意思修改了，也運(yùn)行出來了，希望對你有幫助，代碼附帶在下面：

#includestdio.h

#includemath.h

float t,x1,x2;

void main()

{

void situ1(float a,float b,float c);

void situ2(float a,float b,float c);

void situ3();

float x,a,b,c;

scanf("%f%f%f",a,b,c);

if (a==0)

{

x=-c/b;

printf("x=%.2f\n",x);

}

else

{

t=b*b-4*a*c;

if (t0)

situ1(a,b,c);

else if(t==0)

situ2(a,b,c);

else

situ3();

}

}

void situ1(float a,float b,float c)

{

x1=(-b+sqrt(t))/(2*a);

x2=(-b-sqrt(t))/(2*a);

printf("x1=%.2f\tx2=%.2f\n",x1,x2);

}

void situ2(float a,float b,float c)

{

x1=x2=(-b+sqrt(t))/(2*a);

printf("x1=x2=%.2f\n",x1);

}

void situ3()

{

printf("沒有實(shí)根\n");

}

C語言怎樣設(shè)計(jì)二次函數(shù)，請各位哥哥姐姐幫幫忙，

#include stdio.h

#include stdlib.h

#include math.h

int main()

{

float a,b,c;

float x1,x2,m;

printf("input number a=:");

scanf("%f",a);

printf("input number b=:");

scanf("%f",b);

printf("input number c=:");

scanf("%f",c);

m=b*b-4*a*c;

if(m=0a！=0){

if(m0){

x1=(-b+sqrt(m))/(2*a);

x2=(-b-sqrt(m))/(2*a);

printf("兩根\n");

printf("x1=%f\n",x1);

printf("x2=%f\n",x2);}

else

printf("一根\n");

printf("x1=x2=%f\n",x1);}

else

{

if(a=0 b!=0) printf("根是x=-c/b");

if(a=0b=0) printf("為常函數(shù)")；

if(a!=0) printf("無根\n");

}

system("PAUSE");

return 0; }

c語言：求二次函數(shù)ax^2+bx+c=0的根

#include?stdio.h

#include?math.h

void?main()

{????

float?a,b,c,x1,x2,p,q,disc;????

printf("input?a,b,c\n");????

scanf("a=%f,b=%f,c=%f",a,b,c);????

disc=b*b-4*a*c;

if?(disc0)

{

printf("沒根\n");

}

else

{

p=-b/(2*a);????

q=sqrt(disc)/(2*a);????

x1=p+q;????

x2=p-q;????

printf("\nx1=%5.2f\nx2=%5.2f\n",x1,x2);

}

}

你輸入的那個(gè)方程根本就沒有根，這個(gè)你需要加一個(gè)判斷條件，這樣才能正確處理求根公式

C語言寫二次函數(shù)

首先你已經(jīng)很清楚的說明了你這個(gè)程序是用C語言寫二次函數(shù)的，而當(dāng)a=0時(shí)，就不是二次函數(shù)了，應(yīng)該按照一次函數(shù)來進(jìn)行計(jì)算，否則 一個(gè)數(shù)除以0就沒有意義了.~

#include stdio.h

#include stdlib.h

#include math.h

int main()

{

float a,b,c;

float x1,x2,m;

printf("input number a=:");

scanf("%f",a);

printf("input number b=:");

scanf("%f",b);

printf("input number c=:");

scanf("%f",c);

if(a==0)

printf("一根:%f\n",c*(-1)/b);

else if(a==0b==0)

printf("無意義！");

else

{

m=b*b-4*a*c;

if(m0)

{

printf("兩根\n");

printf("x1=%f\n",(-b+sqrt(m))/(2*a));

printf("x2=%f\n",(-b-sqrt(m))/(2*a));

}

else if(m==0)

printf("x1=x2=%f\n",x1);

}

else

printf("無實(shí)根\n");

}

return 0;

}

c語言解答二次函數(shù)

這個(gè)簡單啊

#includestdio.h

#includemath.h

main()

{

double a,b,c,w;

printf("請輸入三個(gè)數(shù)（方程的系數(shù)），中間用空格分開\n");

scanf("%lf%lf%lf",a,b,c);

w=b*b-4*a*c;

if (w0)printf("方程無解\n");

else if(w==0)printf("方程有一個(gè)解：x=%lf\n",-b/(2*a));

else printf("方程有兩個(gè)解：x1=%lf,x2=%lf\n",(-b+sqrt(w))/(2*a),(-b-sqrt(w))/(2*a));

}

分享標(biāo)題：二次函數(shù)程序c語言,二次函數(shù)c語言函數(shù)編寫
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